-16x^2+12x+10=0

Solution for -16x^2+12x+10=0 equation:

-16x^2+12x+10=0

a = -16; b = 12; c = +10;
Δ = b2-4ac
Δ = 122-4·(-16)·10
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-28}{2*-16}=\frac{-40}{-32}
=1+1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+28}{2*-16}=\frac{16}{-32}
=-1/2
$